Scribe: Madeline Babuka Black
Factoring ax^2+bx+c when a≠1:
HIGHLIGHTS OF BOX METHOD:
factor
| 6x | 9x |
| 2x | 3 |
(right side is 3x on top and 1 on bottom)
1: two numbers that multiply to give you 18 and add to give you 11
2: use sign of whatever lead box would be
EX 9: x^2- 4 ---> (x)^2- (2)^2 ---> (x+2)(x-2)
EX 10: x^4- 121 ---> (x^2)^2- (11)^2 ---> (x^2-11)(x^2-11)
EX 11: 16x^4- 81 ---> (4x^2)^2- (9)^2 ---> (4x^2+9)(4x^2-9) ---> (4x^2+9) ((2x)^2+3^2) ---> (4x^2+9)(2x+3)(2x-3)
*you can sometimes use factoring to solve and equation and find all the zeros
This comment has been removed by the author.
ReplyDeletewhere's our homework posted?
ReplyDeleteNo homework tonight!
ReplyDeleteI dont understand what you mean when you use the sign of the lead box.
ReplyDeletei had a lot of trouble with simplifying radicals on the quiz and i need help with that
ReplyDelete